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The radius of $\mathrm{La}^{3+}$ (Atomic number of $\mathrm{La}=57$ ) is $1.06 Å$. Which one of the following given values will be closest to the radius of $\mathrm{Lu}^{3+}$ (Atomic number of $\mathrm{Lu}=71$ )?
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The correct answer is:
$0.85 Å$
$0.85 Å$
$\Omega \propto \frac{1}{\mathrm{Z}}$
$\frac{\Omega_1}{\Omega_2}=\frac{z_2}{z_1} \Rightarrow \frac{1.06}{\Omega_2}=\frac{71}{57} \Rightarrow \Omega_2=0.85 Å$
$\frac{\Omega_1}{\Omega_2}=\frac{z_2}{z_1} \Rightarrow \frac{1.06}{\Omega_2}=\frac{71}{57} \Rightarrow \Omega_2=0.85 Å$
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