Search any question & find its solution
Question:
Answered & Verified by Expert
The radius of the director circle of the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$, is
Options:
Solution:
1382 Upvotes
Verified Answer
The correct answer is:
$\sqrt{a^2-b^2}$
Equation of director-circle of the hyperbola
$\begin{aligned}
& \frac{x^2}{a^2}-\frac{y^2}{b^2}=1 \text { is } x^2+y^2=a^2-b^2 \\
& \text { So, radius }=\sqrt{a^2-b^2}
\end{aligned}$
$\begin{aligned}
& \frac{x^2}{a^2}-\frac{y^2}{b^2}=1 \text { is } x^2+y^2=a^2-b^2 \\
& \text { So, radius }=\sqrt{a^2-b^2}
\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.