The radius of the first orbit of H 2 is a 0.53 A ∘ , the radius of 25 th orbit will be

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Question: Answered & Verified by Expert

The radius of the first orbit of

H_{2}

is a

0.53 \overset{\circ}{A}

, the radius of

25^{th}

orbit will be

PhysicsAtomic PhysicsNEET

Options:

A $121.5 \overset{\circ}{A}$
B $111 \overset{\circ}{A}$
C $331.25 \overset{\circ}{A}$
D $333 \overset{\circ}{A}$

Solution:

2901 Upvotes Verified Answer

The correct answer is:

331.25 \overset{\circ}{A}

r_{n} \propto n^{2}

∴ r_{25} \propto {(25)}^{2}

∴ \frac{r_{1}}{r_{25}} = \frac{{(1)}^{2}}{{(25)}^{2}} = \frac{1}{625}

∴ r_{25} = 625 \times 0.53 = 331.25 \overset{\circ}{A}

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