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The radius of the light circle observed by a fish at a depth of 12 meter is (refractive index of water $=4 / 3$ )
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Verified Answer
The correct answer is:
$\frac{36}{\sqrt{7}}$
$$
\text { Hints : } r=\frac{h}{\sqrt{\mu^2-1}}=\frac{12}{\sqrt{\frac{16}{9}-1}}=\frac{12 \times 3}{\sqrt{7}}=\frac{36}{\sqrt{7}}
$$
\text { Hints : } r=\frac{h}{\sqrt{\mu^2-1}}=\frac{12}{\sqrt{\frac{16}{9}-1}}=\frac{12 \times 3}{\sqrt{7}}=\frac{36}{\sqrt{7}}
$$
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