Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The radius R of the soap bubble is doubled under isothermal condition. If T be the surface tension of the soap bubble, the work done in doing so is given by
PhysicsMechanical Properties of FluidsJEE Main
Options:
  • A 32πR2T
  • B 24πR2T
  • C 8πR2T
  • D 4πR2T
Solution:
2872 Upvotes Verified Answer
The correct answer is: 24πR2T

The surface energy of a bubble
E = Tension × surface area
E=T×A
For soap bubble
E=2T×A
E=2T×4πR2
Here, R = radius of the bubble
If the radius is doubled then we have
E=2T×4πR2
E=2T×4π2R2
E=32πR2T

Work done = E'-E

 32πR2T-8πR2T=24πR2T

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.