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The range of \( \sec ^{-1} \) is
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The correct answer is:
\( [0, \pi]-\left\{\frac{\Pi}{2}\right\} \)
Given that, \( f(x)=\sec ^{-1} x \)
Since, the given function is not define at \( \frac{\Pi}{2} \). So range of the given function is \( [0, \Pi]-\left\{\frac{\Pi}{2}\right\} \)
Since, the given function is not define at \( \frac{\Pi}{2} \). So range of the given function is \( [0, \Pi]-\left\{\frac{\Pi}{2}\right\} \)
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