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The range of the function defined by $f(x)=\left\{\begin{array}{c}2 x-3, \text { if } x < -1 \\ 1-x^2, \text { if }-1 \leq x \leq 1 \text { is } \\ 3 x^2+2, \text { if } x>1\end{array}\right.$
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The correct answer is:
$(-\infty,-5) \cup[0,1] \cup(5, \infty)$
$f(x)=\left\{\begin{array}{cc}2 x-3 & x < -1 \\ 1-x^2 & -1 \leq x \leq 1 \\ 3 x^2+2 & x>1\end{array}\right.$
Clearly the range is $(-\infty,-5) \cup[0,1] \cup(5, \infty)$
Clearly the range is $(-\infty,-5) \cup[0,1] \cup(5, \infty)$
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