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Question: Answered & Verified by Expert
The range of the real valued function fx=x2+2x+8x2+2x+4 is
MathematicsFunctionsAP EAMCETAP EAMCET 2022 (04 Jul Shift 1)
Options:
  • A 73,
  • B 0,
  • C 1,
  • D 1,73
Solution:
1180 Upvotes Verified Answer
The correct answer is: 1,73

Given fx=x2+2x+8x2+2x+4

=1+4x2+2x+4=1+4x+12+3

We know, 3x+12+3<

0<4x+12+3431<1+4x+12+373

1<1+4x+12+373

Hence, range of fx will be (1,73]

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