Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The rate constant for the first order decomposition of H2O2is given by the following equation: log k = 14.34 – 1.25 × 104K/T Calculate (i) Eafor this reaction and (ii) at what temperature will its half-period be 256 minutes?
ChemistryChemical KineticsNEET
Options:
  • A (i) 239.339 kJ mol–1and (ii) 669K
  • B (i) 239.339 kJ mol–1and (ii) 1028K
  • C (i) 364.223 kJ mol–1and (ii) 669K
  • D (i) 442.528 kJ mol–1and (ii) 669K
Solution:
1062 Upvotes Verified Answer
The correct answer is: (i) 239.339 kJ mol–1and (ii) 669K
Correct Option is : (A)
(i) 239.339 kJ mol–1and (ii) 669K

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.