The rate constant k ′ of one reaction is double the rate constant k ″ of another reaction. Then the relationship between the corresponding activation energies of the two reactions E a ′ and E a ′′ will be - (Assume the pre-exponential factor & temperature to be same)

Question

The rate constant k ′ of one reaction is double the rate constant k ″ of another reaction. Then the relationship between the corresponding activation energies of the two reactions E a ′ and E a ′′ will be - (Assume the pre-exponential factor & temperature to be same), E a ′ > E a ′′, E a ′ = E a ′′, E a ′ E a ′′, E a ′ 4 E a ′′

MARKS App · Accepted Answer

When activation energy decreases, rate constant increases. As k ′ > k ″ , E a ′ E a ′′

Search any question & find its solution

Looking for more such questions to practice?