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The rate constant of a first order reaction at $27^{\circ} \mathrm{C}$ is $10^{-3} \mathrm{~min}^{-1}$. The temperature coefficient of this reaction is 2 . What is the rate constant (in $\mathrm{min}^{-1}$ ) at $17^{\circ} \mathrm{C}$ for this reaction?
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$5 \times 10^{-4}$
Temperature coefficient, $=\frac{k_t+10}{k_t}$
$2=\frac{10^{-3}}{k_t}$
$k_t=\frac{10^{-3}}{2}=\frac{10 \times 10^{-4}}{2}=5 \times 10^{-4}$
$2=\frac{10^{-3}}{k_t}$
$k_t=\frac{10^{-3}}{2}=\frac{10 \times 10^{-4}}{2}=5 \times 10^{-4}$
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