Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The rate constant of a reaction is 1.5×10-s-1 at 27°C and 3×10-s-1 at 127°C . The Ea is
ChemistryChemical KineticsNEET
Options:
  • A 1.663×103 Cal
  • B 3.326×103 cal
  • C 8.314×103 cal
  • D 2.255×103 cal
Solution:
1758 Upvotes Verified Answer
The correct answer is: 1.663×103 Cal
log2×1041.5×104=A2×2.3031300-1400

log2=A2.303×2100400×300

A=0.3010×2.303×2×1200

=1663.68 Cal

=1.663×103 Cal

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.