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The rate of a gaseous reaction is given by the expression $k[A][B]$. If the volume of the reaction vessel is suddenly reduced to $\frac{1}{4}$ th of the initial volume, the reaction rate relating to original rate will be
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16
Rate $=k[A][B]$; when volume is reduced to $\frac{1}{4}$ th, concentration will become 4 times: Therefore, new rate $=k[4 A][4 B]=16 k[A][B]$ $=16$ times
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