Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The rate of change of area of a circle with respect to its radius \( r=2 \mathrm{cms} \) is
MathematicsApplication of DerivativesKCETKCET 2016
Options:
  • A \( 04 \)
  • B \( 2 \pi \)
  • C \( 12 \)
  • D \( 4 \pi \)
Solution:
1596 Upvotes Verified Answer
The correct answer is: \( 4 \pi \)
We know that, area of circle is given by
\[
A=\Pi r^{2}
\]
\[
\text { So, } \frac{d A}{d r}=2 \Pi r
\]
At \( r=2 \mathrm{~cm} \), we have \( \left(\frac{d A}{d r}\right)_{r=2}=4 \Pi \)

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.