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The rate of disintegration of a radioactive sample is $R$ and the number of atoms present at any time $t$ is $N$. When $\frac{R}{N}$ is taken along $Y$-axis and $t$ is taken along $X$-axis, the correct graphs is
Options:
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
Law of radioactive decay is given as,
$\frac{d N}{d t}=-\lambda N$
where, $\frac{d N}{d t}=$ rate of disintegration
So,
$R=-\lambda N \Rightarrow \frac{R}{N}=-\lambda=\text { constant }$
where, $\lambda=$ decay constant
So, the graph $\frac{R}{N}$ versus $t$ is as,
So, the correct graph shown in option (d).
$\frac{d N}{d t}=-\lambda N$
where, $\frac{d N}{d t}=$ rate of disintegration
So,
$R=-\lambda N \Rightarrow \frac{R}{N}=-\lambda=\text { constant }$
where, $\lambda=$ decay constant
So, the graph $\frac{R}{N}$ versus $t$ is as,
So, the correct graph shown in option (d).
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