The ratio of area of orbit of first excited state of electron to the area of orbit of ground state, for hydrogen atom will be

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The ratio of area of orbit of first excited state of electron to the area of orbit of ground state, for hydrogen atom will be

ChemistryStructure of AtomNEET

Options:

A 16:1
B 4:1
C 8:1
D 1:8

Solution:

1959 Upvotes Verified Answer

The correct answer is: 16:1

For first excited state, n = 2

\frac{A_{2}}{A_{1}} = \frac{π r_{2}^{2}}{π r_{1}^{2}}

r_{n} \propto \frac{n^{2}}{Z}

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