Search any question & find its solution
Question:
Answered & Verified by Expert
The ratio of effective number of atoms in a unit cell of fcc and bcc lattices is
Options:
Solution:
1099 Upvotes
Verified Answer
The correct answer is:
$2: 1$
The face-centered cubic (fcc) contains 4 atoms per unit cell while bccc (body-centered cubic) lattices contains 2 atoms per unit cell.
$\frac{\text { Effective number of atoms in fcc }}{\text { Effective number of atoms in bcc }}=\frac{4}{2}=2: 1$
$\frac{\text { Effective number of atoms in fcc }}{\text { Effective number of atoms in bcc }}=\frac{4}{2}=2: 1$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.