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The ratio of energies of photons produced due to transition of electron of hydrogen atom from its (i) second to first energy level and (ii) highest energy level to second energy level is
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The correct answer is:
3:1
Let $E_1$ be the energy of the first energy level
Then $E_2=\frac{E_1}{4}$
Highest level $\mathrm{E}_{\infty}=0$
$\therefore \mathrm{E}_2-\mathrm{E}_1=\frac{\mathrm{E}_1}{4}-\mathrm{E}_1=-\frac{3}{4} \mathrm{E}_1$
$E_{\infty}-E_2=0-\frac{E_1}{4}=-\frac{E_1}{4}$
$\therefore \frac{E_2-E_1}{E_{\infty}-E_2}=3$
Then $E_2=\frac{E_1}{4}$
Highest level $\mathrm{E}_{\infty}=0$
$\therefore \mathrm{E}_2-\mathrm{E}_1=\frac{\mathrm{E}_1}{4}-\mathrm{E}_1=-\frac{3}{4} \mathrm{E}_1$
$E_{\infty}-E_2=0-\frac{E_1}{4}=-\frac{E_1}{4}$
$\therefore \frac{E_2-E_1}{E_{\infty}-E_2}=3$
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