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The ratio of maximum to minimum wavelength in Balmer series hydrogen atom is
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Verified Answer
The correct answer is:
9:5
Maximum wavelength of Balmer series is given by
Minimum wavelength,
Dividing Eq. (2) by Eq. (1)
$$
\frac{\lambda}{\lambda^{\prime}}=\frac{9}{5}
$$
Minimum wavelength,
Dividing Eq. (2) by Eq. (1)
$$
\frac{\lambda}{\lambda^{\prime}}=\frac{9}{5}
$$
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