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The ratio of minimum wavelengths of Lyman and Balmer series will be
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Verified Answer
The correct answer is:
$0.25$
For minimum wavelength,
$\therefore$
$$
\begin{gathered}
\lambda \propto n^{2} \\
\frac{\lambda_{\text {Lyman }}}{\lambda_{\text {Balmer }}}=\left(\frac{1}{2}\right)^{2} \\
\frac{\lambda_{L}}{\lambda_{B}}=\frac{1}{4}=0.25
\end{gathered}
$$
$\therefore$
$$
\begin{gathered}
\lambda \propto n^{2} \\
\frac{\lambda_{\text {Lyman }}}{\lambda_{\text {Balmer }}}=\left(\frac{1}{2}\right)^{2} \\
\frac{\lambda_{L}}{\lambda_{B}}=\frac{1}{4}=0.25
\end{gathered}
$$
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