The ratio of radii of nuclei Al 27 13 and X A 52 is 3 : 5. The number of neutrons in the nuclei of X will be

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Question: Answered & Verified by Expert

The ratio of radii of nuclei

{}_{13}{Al}^{27}

and

{}_{52}X^{A}

is 3 : 5. The number of neutrons in the nuclei of

X

will be

PhysicsNuclear PhysicsNEET

Options:

A $52$
B $73$
C $125$
D $13$

Solution:

1810 Upvotes Verified Answer

The correct answer is:

73

r \propto A^{\frac{1}{3}}

\Rightarrow \frac{3}{5} = {(\frac{27}{A})}^{\frac{1}{3}}

A = 125

N_{n} = A - Z = 125 - 52 = 73

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