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The ratio of solubility of AgCl in 0.1 M KCl solution to the solubility of AgCl in water is:
(Given : Solubility product of $\mathrm{AgCl}=10^{-10}$ )
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(Given : Solubility product of $\mathrm{AgCl}=10^{-10}$ )
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Verified Answer
The correct answer is:
$10^{-4}$
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