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The ratio of the de-Broglie wavelengths for the electron and proton moving with the same velocity is $\left(m_p\right.$-mass of proton, $m_e$-mass of electron)
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The correct answer is:
$m_p: m_e$
As, we know that de-Broglie wave lengths
$\lambda=\frac{h}{m v} \Rightarrow \lambda \propto \frac{1}{m} \text { So, } \frac{\lambda_e}{\lambda_p}=\frac{m_p}{m_e}$
$\lambda=\frac{h}{m v} \Rightarrow \lambda \propto \frac{1}{m} \text { So, } \frac{\lambda_e}{\lambda_p}=\frac{m_p}{m_e}$
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