The ratio of the energy required to raise a satellite upto a height $ h $ above the earth of radius $ R $ to that the kinetic energy of the satellite into that orbit is

Question

The ratio of the energy required to raise a satellite upto a height $ h $ above the earth of radius $ R $ to that the kinetic energy of the satellite into that orbit is, $ \mathrm{R}: \mathrm{h} $, $ h: R $, $ \mathrm{R}: 2 \mathrm{~h} $, $ 2 \mathrm{~h}: \mathrm{R} $

MARKS App · Accepted Answer

Energy required to raise the satellite to a height h from surface of earth is given by, U = - GmM R + h - - GmM R = GMmh R R + h Kinetic energy of satellite is given by, K = 1 2 mv 0 2 = 1 2 m GM R + h ∴ U K = 2 h R

Search any question & find its solution

Looking for more such questions to practice?