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Question: Answered & Verified by Expert
The reaction $\mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{~g}) \rightleftharpoons \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})$ is at equilibrium in a closed vessel at $1000 \mathrm{~K}$. The enthalpy change $(\Delta \mathrm{H})$ for the reaction is $137.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Which one of the following actions would shift the equilibrium to the right ?
ChemistryChemical EquilibriumKVPYKVPY 2017 (5 Nov SB/SX)
Options:
  • A Decreasing the volume of the closed reaction vessel
  • B Decreasing the temperature at which the reaction is performed
  • C Adding an inert gas to the closed reaction vessel
  • D Increasing the volume of the closed reaction vessel
Solution:
1416 Upvotes Verified Answer
The correct answer is: Increasing the volume of the closed reaction vessel
According to Lechatelier principal on increasing volume of closed vessel equilibrium will shift towards right.

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