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The reaction of an alkene $X$ with bromine produce a compound $Y$, which has $22.22 \%$ C, $3.71 \% \mathrm{H}$ and $74.07 \%$ Br. The ozonolysis of alkene $X$ gives only one product. The alkene $X$ is :
[Given: atomic mass of $c=12 ; H=1 ; B r=80]$
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[Given: atomic mass of $c=12 ; H=1 ; B r=80]$
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The correct answer is:
2 -butene
From the data given,
$\mathrm{X}$ will be $\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{Ch}_{3}$ which on ozonolysis gives ethanal.
$\mathrm{X}$ will be $\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{Ch}_{3}$ which on ozonolysis gives ethanal.
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