Search any question & find its solution
Question:
Answered & Verified by Expert
The reaction of ‘tert-butyl methyl ether’ with one equivalent of HI gives
Options:
Solution:
2901 Upvotes
Verified Answer
The correct answer is:
tert-butyl iodide and methanol
When tert-butyl methyl ether reacts with HI, it will formed tert-butyl iodide and methanol.
Since, the tertiary carbocation forms which is stable. So, $\mathrm{S}_{\mathrm{N}} 1$ mechanism followed. Iodine is attached to tertiary C-atom and $-\mathrm{OH}$ group is attached to methyl group.
Since, the tertiary carbocation forms which is stable. So, $\mathrm{S}_{\mathrm{N}} 1$ mechanism followed. Iodine is attached to tertiary C-atom and $-\mathrm{OH}$ group is attached to methyl group.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.