The reaction, ROH + H 2 CN 2 in the presence of HBF 4 , gives the following product, ROCH 3 , RCH 2 OH, ROHCN 2 N 2 , RCH 2 CH 3

ROH + H 2 CN 2 ⟶ HBF 4 ROCH 3 + N 2

The reaction, ROH + H 2 CN 2 in the presence of HBF 4 , gives the following product

Question: Answered & Verified by Expert

The reaction, $\mathrm{ROH}+\mathrm{H}_{2} \mathrm{CN}_{2}$ in the presence of $\mathrm{HBF}_{4}$, gives the following product

ChemistryAminesVITEEEVITEEE 2010

Options:

Solution:

2879 Upvotes Verified Answer

The correct answer is: $\mathrm{ROCH}_{3}$

$\mathrm{ROH}+\mathrm{H}_{2} \mathrm{CN}_{2} \stackrel{\mathrm{HBF}_{4}}{\longrightarrow} \mathrm{ROCH}_{3}+\mathrm{N}_{2}$

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.