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The reagents to carry out the following conversion are
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The correct answer is:
$\mathrm{NaNH}_{2} / \mathrm{CH}_{3} \mathrm{I} ; \mathrm{HgSO}_{4} / \mathrm{dil} \cdot \mathrm{H}_{2} \mathrm{SO}_{4}$
(Here, Me means methyl group) Thus, the correct set of reagents is $\mathrm{NaNH}_{2} / \mathrm{CH}_{3} \mathrm{I} ; \mathrm{HgSO}_{4} / \mathrm{dil} \mathrm{H}_{2} \mathrm{SO}_{4}$
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