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Question: Answered & Verified by Expert
The rear side of a truck is open and a box of mass 2 kg is placed on the truck 8 m away from the open end. The truck starts from rest with an acceleration of 2 m s-2 on a straight road. The box will fall off the truck when it is at distance from the starting point equal to (in meter)

(Given, μ=0.1 and g=10 m s-2 ).
PhysicsLaws of MotionJEE Main
Solution:
1647 Upvotes Verified Answer
The correct answer is: 16
Let a be the acceleration of truck,



For block,



ma-μmg=ma0

a0=a-μg

=2-0.1×10=1 m/s2

8=12a0t2

=12×1×t2

  t=4 s

The block will fall off the truck after 4 s.

For truck,

Distance travelled by the truck in this time.

s=12at2=12×2×42=16  m

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