The refractive index for a prism is given as μ = cot ⁡ A 2 . Then, the angle of minimum deviation in terms of angle of the prism is

Question

The refractive index for a prism is given as μ = cot ⁡ A 2 . Then, the angle of minimum deviation in terms of angle of the prism is, 90 ° - A, 2 A, 180 ° - A, 180 ° - 2 A

MARKS App · Accepted Answer

The refractive index of a prism is given by μ = sin ⁡ A + 5 m 2 sin ⁡ A 2 Where, A = angle of prism δ m = angle of minimum deviation Given, μ = cot ⁡ A 2 = cos ⁡ A 2 sin ⁡ A 2 So, from equation (i) cos ⁡ A 2 sin ⁡ A 2 = sin ⁡ A + δ m 2 sin ⁡ A 2 ⇒ sin ⁡ π 2 - A 2 = sin ⁡ A 2 + δ m 2 ⇒ δ m = π - 2 A ⇒ δ m = 180 ° - 2 A

Search any question & find its solution

Looking for more such questions to practice?