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The refractive index of a prism for a monochromatic wave is $\sqrt{2}$ and its refracting angle is $60^{\circ}$. For minimum deviation, the angle of incidence will be
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$45^{\circ}$
$\mu=\frac{\sin i}{\sin A / 2} \Rightarrow \sqrt{2}=\frac{\sin i}{\sin \left(\frac{60}{2}\right)}$
$\Rightarrow \sqrt{2} \times \sin 30=\sin i \Rightarrow i=45^{\circ}$
$\Rightarrow \sqrt{2} \times \sin 30=\sin i \Rightarrow i=45^{\circ}$
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