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The relative angular speed of hour hand and minute hand of a clock is (in rad/s)
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Verified Answer
The correct answer is:
$\frac{11 \pi}{21600}$
We know angular speed of the hour and minute hand of the clock are given by, $\omega_h=\frac{2 \pi}{12 \times 3600}$ and $\omega_m=\frac{2 \pi}{3600}$ respectively.
Therefore, the relative angular velocity is just the difference between these values:
$\Delta \omega=\frac{2 \pi}{3600}-\frac{2 \pi}{12 \times 3600}=\frac{2 \pi}{3600}\left(\frac{11}{12}\right)=\frac{11 \pi}{21600}$ radians per second
Therefore, the relative angular velocity is just the difference between these values:
$\Delta \omega=\frac{2 \pi}{3600}-\frac{2 \pi}{12 \times 3600}=\frac{2 \pi}{3600}\left(\frac{11}{12}\right)=\frac{11 \pi}{21600}$ radians per second
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