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The remainder when the polynomial $2 x^5-3 x^4+5 x^3-3 x^2+7 x-9$ is divided by $x^2-x-3$ is
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Verified Answer
The correct answer is:
$41 x+3$
$\begin{array}{r}\left.x^2-x-3\right) 2 x^5-3 x^4+5 x^3-3 x^2+7 x-9\left(2 x^3-x^2\right. \\ +10 x+4\end{array}$
$\therefore$ Remainder $=41 x+3$
$\therefore$ Remainder $=41 x+3$
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