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The resistance of a conductivity cell containing $0.001 \mathrm{M}$ KC1 solution at $300 \mathrm{~K}$ is $150 \Omega$. What is the cell constant if conductivity of $\mathrm{KCl}$ solution is $1.5 \times 10^{-} \Omega^{-1} \mathrm{~cm}^{-1}$
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The correct answer is:
$0.225 \mathrm{~cm}^{-1}$
We know $\mathrm{K}=\frac{1}{\mathrm{R}}=\left(\frac{\mathrm{L}}{\mathrm{A}}\right)$
$\begin{aligned} & 1.5 \times 10^{-3}=\frac{1}{150} \times\left(\frac{L}{A}\right) \\ & \frac{L}{A}=0.225 \mathrm{~cm}^{-1}\end{aligned}$
$\begin{aligned} & 1.5 \times 10^{-3}=\frac{1}{150} \times\left(\frac{L}{A}\right) \\ & \frac{L}{A}=0.225 \mathrm{~cm}^{-1}\end{aligned}$
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