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The resistance of a galvanometer is $50 \mathrm{ohms}$ and the current required to give full scale deflection is $100 \mu \mathrm{A}$. In order to convert it into an ammeter, reading upte $10 \mathrm{~A}$, it is necessary to put a resistance of
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$5 \times 10^{-4} \Omega$ in parallel
Resistance in parallel $S=\frac{G i_g}{i-i_g}=\frac{50 \times 100 \times 10^{-6}}{\left(10-100 \times 10^{-6}\right)}$
$\Rightarrow S=5 \times 10^{-4} \Omega$
$\Rightarrow S=5 \times 10^{-4} \Omega$
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