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The resultant of two forces acting at an angle of $120^{\circ}$ is $10 \mathrm{~kg}-\mathrm{W}$ and is perpendicular to one of the forces. That force is
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Verified Answer
The correct answer is:
$\frac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{W}$
From the diagram we get,
$$
\begin{aligned}
\tan 30^{\circ} & =\frac{1}{\sqrt{3}}=\frac{x}{10} \\
\Rightarrow \quad x & =\frac{10}{\sqrt{3}}
\end{aligned}
$$
$$
\begin{aligned}
\tan 30^{\circ} & =\frac{1}{\sqrt{3}}=\frac{x}{10} \\
\Rightarrow \quad x & =\frac{10}{\sqrt{3}}
\end{aligned}
$$
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