Search any question & find its solution
Question:
Answered & Verified by Expert
The resultant of two forces acting at an angle of $120^{\circ}$ is $10 \mathrm{~kg}$-wt and is perpendicular to one of the forces. That force is
Options:
Solution:
1036 Upvotes
Verified Answer
The correct answer is:
$\frac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{wt}$
Here,
$$
\begin{gathered}
\tan 30^{\circ}=\frac{1}{\sqrt{3}} \\
\frac{1}{\sqrt{3}}=\frac{x}{10} \\
x=\frac{10}{\sqrt{3}} \mathrm{~kg}-\mathrm{wt}
\end{gathered}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.