The R.M.S. speed of oxygen molecules at temperature T (in kelvin) is v m s - 1 . As the temperature becomes 4 T and the oxygen gas dissociates into atomic oxygen, then the speed of atomic oxygen

Question

The R.M.S. speed of oxygen molecules at temperature T (in kelvin) is v m s - 1 . As the temperature becomes 4 T and the oxygen gas dissociates into atomic oxygen, then the speed of atomic oxygen, remains the same, becomes 2 v, becomes 2 v, becomes 2 2 v

MARKS App · Accepted Answer

v ∝ γ 1 T v 2 ∝ 2 × γ 2 T 2 = 2 × γ 2 × 4 T ∵ T 2 = 4 T v 2 v 1 = 2 2 γ 2 γ 1 v 2 v 1 = 2 5 × 5 × 2 3 × 7 v 2 = 2 50 21 v v 2 ≅ 2 2 v

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