The root mean square speed of molecules of nitrogen gas at 27 ° C is approximately: (Given mass of a nitrogen molecule = 4 . 6 × 10 - 26 kg and take Boltzmann constant k B = 1 . 4 × 10 - 23 J K - 1 )

Question

The root mean square speed of molecules of nitrogen gas at 27 ° C is approximately: (Given mass of a nitrogen molecule = 4 . 6 × 10 - 26 kg and take Boltzmann constant k B = 1 . 4 × 10 - 23 J K - 1 ), 27 . 4 m s - 1, 91 m s - 1, 1260 m s - 1, 523 m s - 1

MARKS App · Accepted Answer

The RMS value of a gas is given by v rms = 3 R T M = 3 k B T m Substituting the given values, v r m s = 3 × 1 . 4 × 10 - 23 × 300 4 . 6 × 10 - 26 ≈ 523 m s - 1

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