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The self inductance of the motor of an electric fan is $10 \mathrm{H}$. In order to impart maximum power at $50 \mathrm{~Hz}$, it should be connected to a capacitance of
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The correct answer is:
$C=1 \mu F$
$C=1 \mu F$
$f=\frac{1}{2 \pi \sqrt{L C}}$
$C=\frac{1}{4 \times \pi^2 f^2 \times 10}$
$C=1 \mu F$
$C=\frac{1}{4 \times \pi^2 f^2 \times 10}$
$C=1 \mu F$
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