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The semi vertical angle of a right circular cone is $30^{\circ}$. If the height of the cone is $6.125 \mathrm{~cm}$, then the approximate value of the volume of the cone (in cubic $\mathrm{cm}$ ) is
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$(25.5) \pi$
$\begin{array}{rlrl} h =6.125 \mathrm{~cm}, l=?, R=?, \theta=30^{\circ} \\ \therefore \quad \tan 30^{\circ} =R / h \\ \Rightarrow \quad R =h \tan 30^{\circ} \Rightarrow R=6.125 / \sqrt{3} \\ \therefore \quad V_{\text {cone }} =\frac{1}{3} \pi R^2 h=\frac{\pi}{3}\left(\frac{6.125 \times 6.125}{3}\right) \times 6.125 \\ =\pi\left(\frac{229.78}{9}\right)=25.531 \pi \mathrm{cm}^3\end{array}$
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