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The set of quantum numbers for the outermost electron for copper in its ground state is
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The correct answer is:
$4,0,0,+\frac{1}{2}$
The electronic configuration of the Cu atom is
$$
{ }_{29} \mathrm{Cu}=[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{1}
$$
Since, the outermost shell is $4 \mathrm{~s}$, thus outermost electron is in it.
For $4 \mathrm{~s}^{1}$,
$$
\mathrm{n}=4, \quad \mathrm{l}=0, \quad \mathrm{~m}=0, \quad \mathrm{~s}=+\frac{1}{2}
$$
$$
{ }_{29} \mathrm{Cu}=[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{1}
$$
Since, the outermost shell is $4 \mathrm{~s}$, thus outermost electron is in it.
For $4 \mathrm{~s}^{1}$,
$$
\mathrm{n}=4, \quad \mathrm{l}=0, \quad \mathrm{~m}=0, \quad \mathrm{~s}=+\frac{1}{2}
$$
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