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The shaded region in the figure given is the solution of which of the inequations?
Options:
Solution:
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Verified Answer
The correct answer is:
$x+y \leq 7,2 x-3 y+6 \geq 0, x \geq 0, y \geq 0$
The line joining $A(7,0)$ and $(0,7)$ is
$x+y=7$
And the line jojing $C(0,2)$ and $B(3,4)$ is
$2 x-3 y+6=0$
$x, y \geq 0$
The shaded region is bounded by $x+y \leq 7$, $2 x-3 y+6 \geq 0, x \geq 0, y \geq 0$
Hence, option (d) is correct option.
$x+y=7$
And the line jojing $C(0,2)$ and $B(3,4)$ is
$2 x-3 y+6=0$
$x, y \geq 0$
The shaded region is bounded by $x+y \leq 7$, $2 x-3 y+6 \geq 0, x \geq 0, y \geq 0$
Hence, option (d) is correct option.
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