Search any question & find its solution
Question:
Answered & Verified by Expert
The shaded region shown in fig. is given by the inequation
Options:
Solution:
2258 Upvotes
Verified Answer
The correct answer is:
\( 14 x+5 y \geq 70 ; y \leq 14 \) and \( x-y \leq 5 \)
Let points, $A(0,14), B(5,0)$ and $C(19,14)$
Now, equation of side $\mathrm{AB}$ is $\frac{x}{5}+\frac{y}{14}=1$
$\Rightarrow 14 x+5 y=70 \rightarrow(1)$
Equation of side $\mathrm{AC}$ is
$y=14 \rightarrow(2)$
and equation of side $\mathrm{BC}$ is
$x-y=5 \rightarrow(3)$
Therefore, the shaded region shown in figure is given by the inequation
$14 x+5 y>70 y < 14$ and $x-y < 5$
Now, equation of side $\mathrm{AB}$ is $\frac{x}{5}+\frac{y}{14}=1$
$\Rightarrow 14 x+5 y=70 \rightarrow(1)$
Equation of side $\mathrm{AC}$ is
$y=14 \rightarrow(2)$
and equation of side $\mathrm{BC}$ is
$x-y=5 \rightarrow(3)$
Therefore, the shaded region shown in figure is given by the inequation
$14 x+5 y>70 y < 14$ and $x-y < 5$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.