The shortest wavelength of Lyman series of the hydrogen atom is equal to the shortest wavelength of Balmer series of a hydrogen-like atom of atomic number Z . The value of Z is equal to

Question

The shortest wavelength of Lyman series of the hydrogen atom is equal to the shortest wavelength of Balmer series of a hydrogen-like atom of atomic number Z . The value of Z is equal to, 2, 3, 4, 6

MARKS App · Accepted Answer

13 .6 Z 2 1 2 2 - 1 ∞ = 13 .6 1 1 2 - 1 ∞ 2 ⇒ Z = 2

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