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The sides of a right -angled triangle are integers. The length of one of the sides is 12. The largest possible radius of the in circle of such a triangle is
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The correct answer is:
4
$114+(a+r)^{2}=(12+a-r)^{2}$
$\Rightarrow r=\frac{6 a}{a+6}$
$A=6 \quad r=3$
$a=12 \Rightarrow r=4$
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