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Question: Answered & Verified by Expert
The sides of an equilateral triangle are increasing at the rate of $2 \mathrm{~cm} / \mathrm{sec}$. The rate at which the area increases, when side is $10 \mathrm{~cm}$ is:
MathematicsApplication of Derivatives
Options:
  • A
    $10 \mathrm{~cm}^2 / \mathrm{s}$
  • B
    $\sqrt{3} \mathrm{~cm}^2 / \mathrm{s}$
  • C
    $10 \sqrt{3} \mathrm{~cm}^2 / \mathrm{s}$
  • D
    $\frac{10}{3} \mathrm{~cm}^2 / \mathrm{s}$
Solution:
1753 Upvotes Verified Answer
The correct answer is:
$10 \sqrt{3} \mathrm{~cm}^2 / \mathrm{s}$
No Solution Available

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