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The sides of an equilateral triangle are increasing at the rate of $2 \mathrm{~cm} / \mathrm{sec}$. The rate at which the area increases, when side is $10 \mathrm{~cm}$ is:
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The correct answer is:
$10 \sqrt{3} \mathrm{~cm}^2 / \mathrm{s}$
$10 \sqrt{3} \mathrm{~cm}^2 / \mathrm{s}$
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