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The sixth H.M. between 3 and $\frac{6}{13}$ is
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$\frac{63}{120}$
$x_n=\frac{(n+1) a b}{n a+b}$
Sixth H.M.
$x_6=\frac{7.3 .6 / 13}{\left(6.3+\frac{6}{13}\right)}$ $=\frac{126}{240}=\frac{63}{120}$
Sixth H.M.
$x_6=\frac{7.3 .6 / 13}{\left(6.3+\frac{6}{13}\right)}$ $=\frac{126}{240}=\frac{63}{120}$
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