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The sixth term in the expansion of $\left(3-\sqrt{\frac{17}{4}+3 \sqrt{2}}\right)^{10}$ is a
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Verified Answer
The correct answer is:
negative irrational number
We have,
$$
\left(3-\sqrt{\frac{17}{4}+3 \sqrt{2}}\right)^{20} \Rightarrow T_6=-{ }^{20} C_5(3)^5\left(\frac{17}{4}+3 \sqrt{2}\right)^{5 / 2}
$$
$\therefore \mathrm{r}_6=$ negative irrational number
$$
\left(3-\sqrt{\frac{17}{4}+3 \sqrt{2}}\right)^{20} \Rightarrow T_6=-{ }^{20} C_5(3)^5\left(\frac{17}{4}+3 \sqrt{2}\right)^{5 / 2}
$$
$\therefore \mathrm{r}_6=$ negative irrational number
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